Thread: [Help] A Question About Template Specialization

compiled the following code

Code:

class t {
public:
   template <typename T>
   void tt(T i) { }
   template <>
   void tt(int i) { }
};

int main()
{
}

and I got the following error message

5 invalid explicit specialization before '>' token
5 explicit specialization in non-namespace scope `class t'
6 invalid member function declaration

but if I moved function tt out of the class t, say,

Code:

template <typename T>
void tt(T i) { }
template <>
void tt(int i) { }

int main()
{
}

then it compiled well.

I wonder if C++ dosen't support such kind of specialization inside a class? Why? For any good reason?

Anyway, I do need to declare a template function, and a special version of this function, inside a normal class. How? The only alternative is to make it an overloaded function? say,

Code:

class t {
public:
   template <typename T>
   void tt(T i) { }

   void tt(int i) { }
};

int main()
{
}

then it compiled well